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(B) The reaction involves the electrophilic cyclization of a polyene initiated by mercuric acetate $(Hg(OAc)_2)$.$1$. The $Hg(OAc)^+$ electrophile att

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$B$

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(B) The reaction involves the electrophilic cyclization of a polyene initiated by mercuric acetate $(Hg(OAc)_2)$.$1$. The $Hg(OAc)^+$ electrophile attacks the more nucleophilic alkene (the one with the gem-dimethyl group) to form a cyclic mercurinium ion.$2$. This intermediate undergoes a concerted cyclization where the second alkene attacks the electrophilic carbon,leading to the formation of a bicyclic system.$3$. The resulting carbocation is stabilized by the proximity of the electron-withdrawing group $(CO_2CH_3)$.$4$. Finally,the acetate ion $(OAc^-)$ acts as a base to abstract a proton,leading to the formation of the final bicyclic product as shown in option $B$.

The following reaction takes place in high yields. Use your knowledge of alkene chemistry to predict the product.

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